Question

Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes: Isotope $^{36}Ar$ $^{38}Ar$ $^{40}Ar$ Isotopic molar mass $35.96755 g mol^{-1}$$37.96272 g mol^{-1}$$39.9624 g mol^{-1}$ Abundance 0.337% 0.063% 99.600%

Answer 1

The abundance of $^{ 36 }Ar$ = 0.337%  

Atomic mass of $^{ 36 }Ar$ = 35.96755 g.{ mol }^{ -1 }

Therefore, total atomic mass of $^{ 36 }Ar = Abundance \times molar\quad mass$

$= 0.337 \times 35.96755 gmo{ l }^{ -1 }$

Total atomic mass $= 0.121 g/mol$

The abundance of $^{ 38 }Ar$ = 0.063%  

Atomic mass of $^{ 38 }Ar$ = $37.96272 g.{ mol }^{ -1 }$

Therefore, total atomic mass of $^{ 38 }Ar = Abundance \times molar\quad   mass$

$= 0.063 \times 37.96272 g.{ mol }^{ -1 }$

                    Total atomic mass = 0.024 g/mol

The abundance of $^{ 40 }Ar$ = 99.600%

Atomic mass of $^{ 40 }Ar$ = $39.9624 g.mo{ l }^{ -1 }$

Therefore, total atomic mass of $^{ 40 }Ar = Abundance \times molar\quad mass$

                      $= 99.600 \times 39.9624 gmo{ l }^{ -1 }$  

                   Total atomic mass = 39.802 g/mol  

Total molar mass of Argon = Total mass of $^{ 36 }Ar$ + Total mass of $^{ 38 }Ar$ + Total mass of $^{ 40 }Ar$

                                              = 0.121 + 0.024 + 39.802  

                     Total molar mass = 39.947 g/mol

Answer 2

Hey mate....
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TOTAL ATOMIC MASS= 39.802 g/mol

TOTAL MOLECULAR MASS=39.947 g/mol





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