Question

Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes: Isotope $^{36}Ar$ $^{38}Ar$ $^{40}Ar$ Isotopic molar mass $35.96755 g mol^{-1}$$37.96272 g mol^{-1}$$39.9624 g mol^{-1}$ Abundance 0.337% 0.063% 99.600%​

Answer 1

ok

given is the abundance and mass of isotopes of argon

we need to find average atomic mass of argon

that is sum total of percentage *mass of all isotopes by total abundance....

so solution is

A.M of 1st isotope *mass of isotope + a.m og 2nd isotope*mass + a.m of 3rd isotope* mass/100 (total abundance)

=35.96755*0.377 + 37.96242 *0.063 + 39.9624 *99.600/100

=3994.7677557/100

=39.947677557g

rounding off gives 40g