Question

Use the discriminant to determine the number of real roots the equation has. 7x2 + 3x + 1 =0.

(a) One real root (a double root),

(b) Two distinct real roots,

(c) Three real roots,

(d) None (two imaginary roots)​

Answer 1

Answer:

hiii

your answer is here !

Step-by-step explanation:

=> Discriminant = b2 – 4ac

=> Compare the above equation 7x2 + 3x + 1 =0 with ax2 + bx + c = 0

=> We get, a = 7, b = 3, c = 1

=> Put the value of a, b and c;

=> Discriminant = b2 – 4ac

=> Discriminant = (3)2 - 4 × 7 × 1

= 9 – 28

= -19 [13 < 0]

Therefore, discriminant is negative.

So the given equation has none (two imaginary roots).

Answer: (d)

follow me!

Answer 2

Answer:

Use the discriminant to determine the number of real roots the equation has. 7x2 + 3x + 1 =0.

(a) One real root (a double root),✔✔

(b) Two distinct real roots,

(c) Three real roots,

(d) None (two imaginary roots)