Use the distance formula to find the distance of the points AB , BC ,CA where A
(2 ,-1), B(5, 4) and C(3, 2)
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1
Answer:
A(1,−1),B(5,2),C(9,5)
AB=
(5−1)
2
+(2−(−1))
2
=
4
2
+3
2
=
25
=5
BC=
(9−5)
2
+(5−2)
2
=
4
2
+3
2
=
25
=5
CA=
(9−1)
2
+(5−(−1)
2
)
=
8
2
+6
2
=
100
=10
∴ as AB+BC=CA
A,B,C are collinear.
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