Question

Use the elimination method to solve the following system of equations:
3x + 4 = 8y; 5x + 3y +23 = 0 ​

Answer 1

Answer:

x=(-4), y=(-1)

Step-by-step explanation:

3x+4=8y-›3x-8y=(-4)--eq1

5x+3y+23=0-›5x+3y=(-23)--eq2

Multiply eq1 by 5 and eq2 by 3

5×(3x-8y=(-4))-›15x-40y=(-20)--eq3

3×(5x+3y=(-23))-›15x+9y=(-69)--eq4

Add eq3 and eq4, we get

49y=(-49)

y=(-49)/49

y=(-1)

Substitute y=(-1) in eq1

3x-8y=(-4)

3x-8(-1)=(-4)

3x+8=(-4)

3x=(-4)-8

3x=(-12)

x=(-12)/3

x=(-4)