Question

use the expansion of (a+b)^2 or (a-b)^2 evaluate (2.05)^2 and (5.94)^2​

Answer 1

SOLUTION

TO DETERMINE

The value of (2.05)² & (5.94)²

FORMULA TO BE IMPLEMENTED

$\sf{1. \: \: {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} }$

$\sf{2. \: \: {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} }$

EVALUATION

1.

$\sf{ {(2.05)}^{2} }$

$\sf{ = {(2 + 0.05)}^{2} }$

$\sf{ = {(2)}^{2} + 2 \times 2 \times 0.05 + {(0.05)}^{2} }$

$= 4 + 0.2 + 0.0025$

$= 4.2025$

2.

$\sf{{(5 .94)}^{2} }$

$\sf{ = {(6 - 0.06)}^{2} }$

$\sf{= {(6)}^{2} - 2 \times 6 \times 0.06 + {(0.06)}^{2} }$

$= 36 - 0.72 + 0.0036$

$= 35.2836$

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