Question

Use the expression f=q(v x b), to define the si unit of magnetic field

Answer 1

Answer:

in S.I system unit of magnetic field is weber/meter^ or tesla (T) or newton per ampere metre

Step-by-step explanation:

the expression for magnetic field is f=q(v×b)

if v and b both are normal to each other then f=qvb

now q=1 , v=1 then f=b

hence,the magnetic field at a point is equal to the force which a unit charge experiences when it enters with unit velocity in a direction normal to the direction of magnetic field at that point

Answer 2

S.I unit of magnetic field is Tesla(T)

Step-by-step explanation:

Given expression:

$f=q(v\times b)$

$f=qvbsin\theta$

Where v=Magnitude of vector v

Magnitude of vector b=b

Using $a\times b=\mid a\mid \mid b\mid sin\theta$

$\theta=90^{\circ}$

Because the angle between velocity and magnetic field vector=90 degree

Substitute the values

$f=qvbsin90=qvb$

Because $sin90^{\circ}=1$

$b=\frac{f}{qv}$

Where f=Force applied on charge q

q=Charge

v=Velocity of charge

b=Magnetic field

S.I unit of force= N(Newton)

S.I unit of velocity=m/s

S.I unit of charge=C

$b=\frac{N}{C\cdot ms^{-1}}=\frac{Ns}{mC}=Tesla(T)$

S.I unit of magnetic field is Tesla(T).

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