Question

use the factor theorem tho determine whether g(x)=x+1 is a factor of f(x)=5x3+x2-5x-1​

Answer 1

Step-by-step explanation:

g(x) = x+1

then, g(x) = 0

so, x+1 = 0

x = -1

now f(x) = 5x³+x²-5x-1

f(x) = 0

now, f(-1) = 5(-1)³+(-1)²-5(-1)-1

f(-1) = -5+1+5-1

f(-1) = 0

therefore the condition g(x) = x+1 is satisfying the equation and g(x) = x+1 is a factor of f(x) = 5x³+x²-5x-1.

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Answer 2

Answer:

g(x)=x+1

g(x)=x+1=0

g(x)=x=_1

f(_1)=5(_1)cube+(_1)^_5(_1)_1

f(_1)=_5+1+5_1

f(_1)=0