use the factor theorem to determine g(x) is a factor of P(x) in the following case p(x)=2x³+x²-2x+1 and g(x)=x +1
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Step-by-step explanation:
g(x)= 0
x+1=0
x= —1
put the x= —1 in p(x)
p(—1)= 2×(—1)³+ (-1)²— 2×—1+1
p(—1)= —2+1+2+1
p(—1)= 2
so, x—1 is not a factor of p(x).
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