Question

Use the factor Theorem to determine
Whether 8(x) is a factor of p(x)
p(x) = 2x³+x³-2x-1, g(x)=x+1​

Answer 1

here p(x)= 2x³+x²-2x-1

zero of x+1 is -1

now p(-1)= 2(-1)³+(-1)²-2(-1)-1

=-2+1+2-1=0

then by factor theorem g(x) is a factor of p(x)

Answer 2

Answer:

no 8(x) is not a factor of p(x)

p(x) = 2x³+x³-2x-1, g(x)=x+1

Step-by-step explanation:

see the pic that I have attach

hope this answer is helpful

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