Use the factor theorem to determine whether g(x) is a factor of f(x) in each of the
following cases:
(i) f(x) = x3 - 3x2 + 4x - 4, g(x) = x - 2
(ii) f(x)=2.3x2 + 5x + V2, g(x)=x + 12
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Answer:
(i) g(x)=0
x-2=0
x=2
so,zero of g(x) is 2.
now,f(2)= (2)^3-3(2)^2+4(2)-4
=8-12+8-4
=-4+4
=0
therefore,by factor theorem,g(x) is a factor of f(x).
(ii)g(x)=0
x+12=0
x=-12
so zero of g(x) is -12.
now,f(-12)=2.3(-12)^2+5(-12)+(-12)^2
=331.2-60+144
=415.2
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