Question

(Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the cases) ​

Answer 1

Answer:

Step-by-step explanation:

Given P(x)=x³+3x²+3x+1

G(x)=x+2

P(-2)= (-2)³+3×(-2)²+3×-2+1

= -8+12-6+1

=-14+13

=-1 hence G(X) IS NOT A FACTOR OF p(x)

2)) P(x)=x³-4x²+x+6

G(x)=x-3

P(3)=3³-4×9+3+6

=36-36

=0

Hence by factor theorem G(x) is divisible by P(X)

Hope this helps

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