use the factor theorem to determine whether g(x) is a factor of p(x) in each of the following cases:
1) p(x) = x³ - 3x² -10x + 24 , g(x) = x-4
2) p(y) = y³ - 4y² + y + 6 , g(y) = y - 3
Answers
Answered by
1
Answer:
Yeah in each of the cases g(x) is a factor of p(x).
Step-by-step explanation:
please mark me brainliest if I am right.
Answered by
0
solution
Step-by-step explanation:
P(x)=x
3
+4x
2
+x−6
g(x)=x−3
p(x)=x
3
−4x
2
+x+6
p(3)=(3)
2
−4(3)
2
+3+6
27−4(9)+3+6
=27−36+3+6
=27−36+3+6
36−36
p(3)=0
Here , we have r(x)=p(a)=0
∴(x−3) is the factor of p(x)
Similar questions