Question

use the factor theorem to determine whether g(x) is factor of p(x) in each of the following cases
(iii) p(x)= x3 – 4x2 + x +6, g(x) = x - 3​

Answer 1

Explanation:

(iii) p(x) = x3 – 4x2 + x + 6, g(x) = x – 3

Apply remainder theorem

=>x - 3 =0

=> x = 3

Replace x by – 2 we get

=>x3 – 4x2 + x + 6

=>(3)3 -4(3)2 + 3 + 6

=> 27 - 36 +3 + 6

=> 0

Remainder is equal to 0 so that x-3 is a factor of x3 – 4x2 + x + 6

Answer 2

Answer:

x-3÷x³-4x²+x+6= 0

Explanation:

Yes, g(x) is a factor of p(x)

hopefully it's helpful