use the factor theorem to determine whether g(x) is factor of p(x) in each of the following cases.
1. p(x) =2x³+x²-2x-¹
g(x) =x+1.
2.p(x)=4x²+x+6
g(x)=x-3
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Step-by-step explanation:
1 ) Apply factor theorem
x+1=0
So x=−1
2x3+x2−2x−1
Replace x by −1, we get
2(−1)3+(−1)2−2(−1)−1=−2+1+2−1=0
Reminder is 0 so that x+1 is a factor of 2x3+x2−2x−1
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