Question

Use the Factor Theorem to determine whether
ollowing cases:
Ax) = 5x + 7 - 5x-1, g(x)=x+1
) Ax) = 7+3+ + 3x + 1, g(x)=x+1
Ax) = x - 4x2 ++6. g(x) = x - 2
Ax) = 3x +7-20x + 12, g(x) = 3x - 2
Ax)= 47° + 204 +
o





33x + 18, g(x) = 2x + 3​

Answer 1

Given : f(x)=5x³+x²-5x-1,  g(x)=x+1  

To Find :  Whether g(x) is  a factor of f(x) or not

Solution:

f(x)=5x³+x²-5x-1,  

g(x)=x+1  

x + 1 = 0

=> x = - 1

g(x) will be factor if f(-1) = 0

x- a is  a factor of f(x) if f(a) = 0

f(x)=5x³+x²-5x-1,  

f(-1)  = -5 + 1 + 5 - 1

=> f(-1)  = 0

Hence (x + 1) is a factor of  =5x³+x²-5x-1,

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