use the factor theorum to factoraize 3x³+2x²-19x+6
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3x³ + 2x² - 19x + 6 =
= (x - 2)(3x² + 8x - 3)
= (x - 2)(3x - 1)(x +3)
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ANSWER .... (3x-1)(x+3)(x-2)
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