Question

Use the following data to construct a Born-Haber cycle and calculate the lattice energy of BaS. Ba2+(g) + S2-(g)  BaS (s) LE? Ba(s) + S(s)  BaS (s) ΔHθf = -460 kJ/mol Ba(s) + S(s)  Ba(g) + S(s) ΔHθat =+180 kJ/mol Ba(g) + S(s)  Ba+(g) + S(s) + e- ΔHθIE =+502 kJ/mol Ba+(g) + S(s) + e-  Ba2+(g) + S(s) + 2e- ΔHθIE2=+966kJ/mol Ba2+(g) + S(s) + 2e-  Ba2+(g) + S(g) + 2e- ΔHθat =+279 kJ/mol Ba2+(g) + S(g) + e-  Ba2+(g) + S-(g) + e- ΔHθEA= -200 kJ/mol Ba2+(g) + S-(g)  Ba2+(g) + S2-(g) ΔHθEA2=+640kJ/mol

Answer 1

Answer:

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