Question

Use the following information in the given figure to prove :
(i) AB = FE
(ii) BD = CF​

Answer 1

Step-by-step explanation:

In∆CAB&∆FDE

AC=DE. (GIVEN)

<ACB=<FDE. (GIVEN)

<CBA= <DFE. (aternate interior angles)

∆CAB~=∆FDE (By AAS Congruence criterion)

AB=FE. (By CPCT)

BD=CF. (By CPCT)

Answer 2

Step-by-step explanation:

In ∆ ABC& ∆ EFD

AC=ED

angleACB = angle EDF

hence∆ ABC is similar to ∆ EFD

so, AB/FE= AC/ DE [ GIVEN THAT AC=DE]

HENCE. AB= FE

NOW the ∆ABC is congruent to ∆ EFD

SO, BC=FD [ BC=BD+DC, FD= FC+DC]

therefore BD= FC

HENCE PROOF.

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MARK AS BRAINLIST