Question

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A milkman has two types of milk A and B. Type A has 90% pure milk and 10% water while type B has 95% pure milk and 5% water
How many respective litres of each type A and B of milk should the milkman mix to obtain 30 litres of 92% pure milk?

Answer 1

18 and 12 liters of each type of milk should the milkman mix to obtain 30 liters of 92% pure milk.

Given that,

A and B are two kinds of milk that a milkman has. While type B contains 95% pure milk and 5% water, type A contains 90% pure milk and 10% water.

We have to find the milkman needs to combine how many liters of milk types A and B in order to get 30 liters of 92% pure milk.

We know that,

Type A contains milk be 90%

Type B contains milk be 95%

To get the milkman have 92% of milk

We have

Type A = (95-92) = 3  

Type B = (92-90) = 2

A and B of each type mixes in ratio 3 : 2

In 30 liters of mixture,

Type A mixed = $\frac{3}{5}$×30 = 18 liters

Type B mixed = $\frac{2}{5}$×30 = 12 liters

Therefore, 18 and 12 liters of each type of milk should the milkman mix to obtain 30 liters.

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