use the formula to find the values
1)97×103
2)54×46
3)98×102
aliyashaikh18:
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Answers
Answered by
12
1)97*103=
(100-3)(100+3)
(100)^2+(3-3)(100)-3*3
10000-9
=9991
2) 54*46
(50+4)(50-4)
(50)^2+(4-4)(50)-4*4
2500-15
=2484
3)98*102
(100-2)(100+2)
(100)^2+(2-2)(100)-2*2
10000-4
=9996
hope you got the answer please mark it as brainliest
(100-3)(100+3)
(100)^2+(3-3)(100)-3*3
10000-9
=9991
2) 54*46
(50+4)(50-4)
(50)^2+(4-4)(50)-4*4
2500-15
=2484
3)98*102
(100-2)(100+2)
(100)^2+(2-2)(100)-2*2
10000-4
=9996
hope you got the answer please mark it as brainliest
Answered by
6
Hey, sup!
We'll use the formula (a-b)(a+b)=a^2-b^2.
As per the question,
1) 97×103.
=(100-3)×(100+3).
=100^2 - 3^2.
=10000-9.
=9991.
2) 54×46.
=(50+4)×(50-4).
=50^2 - 4^2.
=2500-16.
=2484.
3) 98×102.
= (100-2)×(100+2).
=100^2 - 2^2.
=10000-4.
=9996.
Hope it helps.
We'll use the formula (a-b)(a+b)=a^2-b^2.
As per the question,
1) 97×103.
=(100-3)×(100+3).
=100^2 - 3^2.
=10000-9.
=9991.
2) 54×46.
=(50+4)×(50-4).
=50^2 - 4^2.
=2500-16.
=2484.
3) 98×102.
= (100-2)×(100+2).
=100^2 - 2^2.
=10000-4.
=9996.
Hope it helps.
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