Use the formula v = (√ργ/ρ) to explain why the speed of sound in air increases with humidity.
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speed of sound is given by ![v=\sqrt{\frac{\gamma P}{\rho}} v=\sqrt{\frac{\gamma P}{\rho}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B%5Cgamma+P%7D%7B%5Crho%7D%7D)
where v is the speed of sound in air,
is adiabatic coefficient
P is pressure and
is density
actually, density of moist air is less than density of dry air. or you can say that if humidity increases, density of air decreases.
but in a above formula, we know speed of sound is inversely proportional to square root of density of sound in air.
hence, speed of sound increase with humidity due to decrease density.
where v is the speed of sound in air,
P is pressure and
actually, density of moist air is less than density of dry air. or you can say that if humidity increases, density of air decreases.
but in a above formula, we know speed of sound is inversely proportional to square root of density of sound in air.
hence, speed of sound increase with humidity due to decrease density.
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