use the general power rule to find the differential coefficient of (1-x^2)^5
Answers
Answer:
The Power rule also allows us to differentiate expressions like \sqrt x
x
square root of, x, end square root or x^{^{\frac{2}{3}}}x
3
2
x, start superscript, start superscript, start fraction, 2, divided by, 3, end fraction, end superscript, end superscript. Consider this differentiation of \sqrt x
x
square root of, x, end square root:
\begin{aligned} \dfrac{d}{dx}\sqrt x&=\dfrac{d}{dx}\left(x^{^{\Large\frac{1}{2}}}\right)\quad\gray{\text{Rewrite as power}} \\\\ &=\dfrac{1}{2}\cdot x^{^{\Large-\frac{1}{2}}}\quad\gray{\text{Power rule}} \\\\ &=\dfrac{1}{2\sqrt x}\quad\gray{\text{Rewrite as radical}} \end{aligned}
dx
d
x
=
dx
d
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⎜
⎛
x
2
1
⎠
⎟
⎞
Rewrite as power
=
2
1
⋅x
−
2
1
Power rule
=
2
x
1
Rewrite as radical
Answer:
1 - x power 10 . hope you understand well .