Question

Use the given conditions to write an equation for the line in​ point-slope form and in​ slope-intercept form.  
​x-intercept = -1/2
and​ y-intercept = 5

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let's start by finding the slope of this line. If the x-intercept is -2, then then line crosses the x-axis when x = -2. That means the coordinates of that point is (-2, 0). The y-intercept is 10, so the coordinates are (0, 10).

Use those two points to find the slope using Δy / Δx .

m = y1-y2 / x1-x2

m = 0 - 10 / -2 - 0

m = -10 / -2

m = 5

Point slope formula is y - y1 = m (x - x1). m is the slope, which we just found out, and y1 and x1 are the coordinates of any point on the line. So if we choose (-2, 0) and plug it into the equation, we get:

y - 0 = 5 (x - -2)

We could also use the other coordinate to get:

y - 10 = 5 (x - 0)

Both of these equations are equal to each other (simplify them if you don't believe me!)

Slope intercept form is y = mx + b, where b is the y-intercept. We already know m, and the y-intercept is given as 10, so plug them in and we get:

y = 5x + 10