use the heron formulae to find the area of the triangle whose sides are 13 cm,14 cm and 15 cm.
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Answered by
15
a = 13 cm
b = 14 cm
c = 15 cm
S = ( 13 + 14 + 15) /2
=> S = 42 / 2
=> S = 21
Area = sqrt [ s(s-a) (s-b) (s-c)]
= sqrt [ 21 (21-13) (21-14)(21-15)]
= sqrt ( 21 × 8 × 7 × 6)
= sqrt ( 3 × 7 × 2 × 2 × 2 × 7 × 2 × 3)
= 3 × 7 × 2 × 2
= 84 cm^2
b = 14 cm
c = 15 cm
S = ( 13 + 14 + 15) /2
=> S = 42 / 2
=> S = 21
Area = sqrt [ s(s-a) (s-b) (s-c)]
= sqrt [ 21 (21-13) (21-14)(21-15)]
= sqrt ( 21 × 8 × 7 × 6)
= sqrt ( 3 × 7 × 2 × 2 × 2 × 7 × 2 × 3)
= 3 × 7 × 2 × 2
= 84 cm^2
Answered by
0
a = 13 cm
b = 14 cm
c = 15 cm
S = ( 13 + 14 + 15) /2
=> S = 42 / 2
=> S = 21
Area = sqrt [ s(s-a) (s-b) (s-c)]
= sqrt [ 21 (21-13) (21-14)(21-15)]
= sqrt ( 21 × 8 × 7 × 6)
= sqrt ( 3 × 7 × 2 × 2 × 2 × 7 × 2 × 3)
= 3 × 7 × 2 × 2
= 84 cm^2
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