use the identitie to find the product
* (x + a) (x + b)= xsquare + (a+b) x+ ab
1) (x-5) (x-5)
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Therefore, the product of special binomials x+a and x+b can be expanded as x2+(a+b)x+ab x 2 + ( a + b ) x + a b in algebra.(x-a)(x-b) is equal to x^2-xb-ax-ab= x^2 -x(b+a) –ab or = x^2 -b(x+a) –ax. 20, 2016....
Step-by-step explanation:
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Step-by-step explanation:
Ok, so in (x+a)(x+b) take a = b because (x-5)(x-5) you see that -5 = -5
Now,
use distributive property on (x+a)(x+b) twice, you will get x^2 + 2ax + a^2
A represents the constant(AKA a and b)
Now that you have the equation, just plug -5 in for a and x for x.
If you do that, then you will find that x^2 -10x + 25 is the answer.
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