Math, asked by Kaus444, 8 months ago

Use the identity (a+b)^2=a^2+b^2+2ab to evaluate (41)^2+(40)^2​

Answers

Answered by prakrutidas48
4

Answer:

Step-by-step explanation:

From the identity

a^2+b^2 =(a+b)^2-2ab

So... 41^2+40^2=(40+41)^2-2*41*42

=81^2-3280

=6561-3280=3281

HOPE IT WILL HELP YOU

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