use the identity method of (41) square
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Answered by
8
(40+1)2
(a+b)2=a2+b2+2ab
put it by this identity
(40)2+(1)2+2(40)(1)
1600+1+80
1681
(a+b)2=a2+b2+2ab
put it by this identity
(40)2+(1)2+2(40)(1)
1600+1+80
1681
janash:
mark it as brainliest
Answered by
4
Hi,
Thank you for asking this question.
Here is the required answer:-
Let us first split 41 as,
40+1
Now we can write as,
(40+1)square or (40+1)^2
Now we can solve this by setting the formula,
(a+b)square or (a+b)^2
(a)^2 + 2 × b × 1 + (b)^2
a^2 + 2ab + b^2
Hence,
We can write,
(40)^2 + 2 × 40 × 1 + (1)^2
1600 + 80 + 1
1681
So,
(41) square = 1681
Hope my answer helped you my friend.
Thank you for asking this question.
Here is the required answer:-
Let us first split 41 as,
40+1
Now we can write as,
(40+1)square or (40+1)^2
Now we can solve this by setting the formula,
(a+b)square or (a+b)^2
(a)^2 + 2 × b × 1 + (b)^2
a^2 + 2ab + b^2
Hence,
We can write,
(40)^2 + 2 × 40 × 1 + (1)^2
1600 + 80 + 1
1681
So,
(41) square = 1681
Hope my answer helped you my friend.
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