Question

Use the identity (x + a x + b) = x^2 + (a + b) x +ab to evaluate the following.
A.(x+ 1) ×(x + 6)
B. (3a+4b) x (3a+2b)
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Answer 1

Step-by-step explanation:

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a) =>x²+(1+6)x+6

=x²+7x+6

$\mathscr{AND}$

b)=>9a²+(4b+2b)3a+8b²

=9a²+18ab+8b²

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Answer 2

Step-by-step explanation:

(x + a) (x + b) = x^2 + (a + b) x + ab

A.(x+ 1) × (x + 6)

a = 1

b = 6

$= {x}^{2} + (1 + 6)x + 6(1) \\ = {x}^{2} + 7x + 6$

B. (3a+4b) x (3a+2b)

x = 3a

a = 4b

b = 2a

=$({3a})^{2} + (4a + 2b)3a + (4b)(2b) \\ </strong><strong>=</strong><strong>9 {a}^{2} + (6b)(3a) + (4b)(2b) \\</strong><strong>=</strong><strong> 9 {a}^{2} + 18ab \: + 8 {b}^{2}$