use the identity (x+a) (x + b) = x² + (a+b)x+ab to find the value of (p-1/2)×(p-1/5)
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Answer:
p^2+(-7/10)p+(1/10)
Step-by-step explanation:
[p+(-1/2)]*[p+(-1/5)]=p^2+[(-1/2)+(-1/5)]p+(-1/2)(-1/5)
=p^2+[(-5-2)/10]p+(1/10)
=p^2+(-7/10)p+(1/10)
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