Question

Use the laws of exponents and simplify: $\frac{2^{3^2}} {(2^{3})^2}}$

Answer 1

Solution :

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We know the Exponential laws :

i ) ( a^m )ⁿ = a^mn

ii ) a^m/a^n = a^m-n

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Now ,

[ 2^3² ]/( 2³ )²

= ( 2^9 )/2^6

= 2^9-6

= 2³

= 8

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Answer 2

hope this helps........