use the method pedmas and Bodmas 7-(14÷1+1-3)
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op
- techno gamerz
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Answered by
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Answer:
7-(14÷1+1-3)
7-(14+1-3)
7-(15-3)
7-(12)
7-12
-5
BODMAS
BO - Bracket open
D - Division
M - Multiplication
A - Addition
S - Subtraction
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