Math, asked by shajikbenny, 9 months ago

use the numbers 1,2,3,4,5,6,7,8 and 9 only once in the blanks and complete the table​

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Answers

Answered by BarunKumarDalai
1

Answer:

Given : Operators and 9 blank spaces , BODMAS rule to be applied.

To find : Fill the numbers from 1 to 9

Solution:

58 can be 7 * 8 + 2 or 6 * 9 + 4

Lets take case 1

7 * 8 + 2

in top row it can not be 7 as Division is there and sum is only 7

possible top row

2 + 8 ÷ 4 = 4

but 2 is required in 7 * 8 + 2

Hence this solution not possible

now lets take

Middle column 6 * 9 + 4

in top row 9 can not be there

top row can be

2 + 6 ÷ 3 = 4 or 1 + 6 ÷ 2 = 4

in middle row - 9 is there

hence middle row can

be 7 - 9 + 8 = 6 or 8 - 9 + 7 = 6

2 + 8 * 1 = 10 or 3 + 7 * 1 = 10

so one will be at bottom hence

top row can not be 1 + 6 ÷ 2 = 4

so Top row become 2 + 6 ÷ 3 = 4

Hence last column become 3 + 7 * 1 = 10

middle Row become 8 - 9 + 7 = 6

1st Column becomes 2 * 8 - 5 = 11

Bottom row become 5 + 4 + 1 = 10

Hence Solutin

2 + 6 ÷ 3 = 4

× × +

8 - 9 + 7 = 6

- + ×

5 + 4 + 1 = 10

= = =

11 58 10

Answered by SwaggerGabru
0

Solution:

58 can be 7 * 8 + 2 or 6 * 9 + 4

Lets take case 1

7 * 8 + 2

in top row it can not be 7 as Division is there and sum is only 7

possible top row

2 + 8 ÷ 4 = 4

but 2 is required in 7 * 8 + 2

Hence this solution not possible

now lets take

Middle column 6 * 9 + 4

in top row 9 can not be there

top row can be

2 + 6 ÷ 3 = 4 or 1 + 6 ÷ 2 = 4

in middle row - 9 is there

hence middle row can

be 7 - 9 + 8 = 6 or 8 - 9 + 7 = 6

2 + 8 * 1 = 10 or 3 + 7 * 1 = 10

so one will be at bottom hence

top row can not be 1 + 6 ÷ 2 = 4

so Top row become 2 + 6 ÷ 3 = 4

Hence last column become 3 + 7 * 1 = 10

middle Row become 8 - 9 + 7 = 6

1st Column becomes 2 * 8 - 5 = 11

Bottom row become 5 + 4 + 1 = 10

Hence Solutin

2 + 6 ÷ 3 = 4

× × +

8 - 9 + 7 = 6

- + ×

5 + 4 + 1 = 10

= = =

11 58 10

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