Question

Use the pendulum equation to calculate the period of a 1.50 m pendulum. remember that the value of "g" is 9.81 m/s2.

Answer 1

T = 2π
$\sqrt{l \div g}$
T = 2 X 3.142 x
$\sqrt{1.50 \div 9.81}$
(T)² = 6.284 x 0.1529 = 0.9608
T =
$\sqrt{0.9608}$

T = 0.98 sec