Question

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Answer 1

Answer:

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Answer 2

Answer:

In ∆PQS < QPS = 60°

given, the other two angles of ∆PQS are both x

we know sum of all the angles of a triangle is 180°

therefore,

2x + 60 ° = 180°

or; 2x = 120°

or; x = 60 °

so, the value of x is 60°

In ∆QRS, < QRS = 30°

and, the other angles are y

therefore, it's an isosceles triangle.

therefore,

2y + 30° = 180 °

or; 2y = 150 °

or; y = 75 °