use the properties of sets to prove that for all the sets Aand B A difference A intersection B
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A – (A ∩ B) = A ∩ (A ∩ B)′ (since A – B = A ∩ B′)
= A ∩ (A′ ∪ B′) [by De Morgan’s law)
= (A ∩ A′) ∪ (A ∩ B′) [by distributive law]
= φ ∪ (A ∩ B′)
= A ∩ B′ = A – B
hope it helps u !!
Answered by
1
Answer:
We have A – (A ∩ B) = A ∩ (A ∩ B)′ (since A – B = A ∩ B′)
= A ∩ (A′ ∪ B′) [by De Morgan’s law)
= (A ∩ A′) ∪ (A ∩ B′) [by distributive law]
= φ ∪ (A ∩ B′) = A ∩ B′ = A – B
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