use the remainder theorem to factorise2x^3+9x^2+7x-6 hence solve the equation 2x^3+9x^2+7x-6=0
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Here is the answer
p(x) = 2x³ + 9x² + 7x - 6
p(-2) = 2(-2)³ + 9(-2)² + 7(-2) - 6
p(-2) = 2(-8) + 9(4) +7(-2) - 6
p(-2) = -16 + 36 - 14 - 6
p(-2) = 36 - 36
p(-2) = 0
Hence Solved
Have a Good Day ☀
p(x) = 2x³ + 9x² + 7x - 6
p(-2) = 2(-2)³ + 9(-2)² + 7(-2) - 6
p(-2) = 2(-8) + 9(4) +7(-2) - 6
p(-2) = -16 + 36 - 14 - 6
p(-2) = 36 - 36
p(-2) = 0
Hence Solved
Have a Good Day ☀
nividhasharma2701:
I want the solution for the second part of the question that is,Hence solve the same equation
I can't understand that. Do you want the factors of the following equation?
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