Use the remainder theorem to find the remainder, when
(2x – 1)
3
+ 6(3 + 4x)
2
is divided by 2x + 1
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Step-by-step explanation:
Let f(x) = 4x3– 5x + 1
a) When f(x) is divided by x – 2, remainder,
R = f(2) = 4(2)3– 5(2) + 1 = 23
b) When f(x) is divided by x + 3, remainder,
R = f(–3) = 4(–3)3– 5(–3) + 1 = –92
c) When f(x) is divided by 2x – 1, remainder,
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