Question

Use the remainder theorem to find the remainder, when

(2x – 1)

3

+ 6(3 + 4x)

2

is divided by 2x + 1

​

Answer 1

Answer:

Given p(x) = x3 – 2x2 – 4 – 1 and g(x) = x + 1 Here zero of g(x) = – 1 By using the remainder theorem P(x) divided by g(x) = p( – 1) P ( – 1) = ( – 1)3 – 2 ( – 1)2 – 4 ( – 1) – 1 = 0 Therefore, the remainder = 0 (ii) given p(x) = x3 – 3x2 + 4x + 50, g(x) = x – 3 Here zero of g(x) = 3 By using the remainder theorem p(x) divided by g(x) = p(3) p(3) = 33 – 3 × (3)2 + 4 × 3 + 50 = 62 Therefore, the remainder = 62 (iii) p(x) = 4x3 – 12x2 + 14x – 3, g(x) = 2x – 1 Here zero of g(x) = ½ By using the remainder theorem p(x) divided by g(x) = p (½) P( ½ ) = 4( ½ )3 – 12( ½ )2 + 14 ( ½ ) – 3 = 4/8 – 12/4 + 14/2 – 3 = ½ + 1 = 3/2 Therefore, the remainder = 3/2 (iv) p(x) = x3 – 6x2 + 2x – 4, g(x) = 1 – 3/2 x Here zero of g(x) = 2/3 By using the remainder theorem p(x) divided by g(x) = p(2/3) p(2/3) = (2/3)3 – 6(2/3)2 + 2(2/3) – 4 = – 136/27 Therefore, the remainder =

mark as brainliest plz