Use the remainder theorem to find the value of k,it being given that when x3+2x2+kx+3 is divided by (x-3),then remainder is 21.
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Answered by
70
using remainder theorem
x = 3
x^3 + 2x^2 + kx + 3 = 21
( 3 )^3 + 2 ( 3 )^2 + k ( 3 ) + 3 = 21
27 + 18 + 3k + 3 = 21
3k = 21 - 48
3k = - 27
k = - 27 / 3
k = - 9
x = 3
x^3 + 2x^2 + kx + 3 = 21
( 3 )^3 + 2 ( 3 )^2 + k ( 3 ) + 3 = 21
27 + 18 + 3k + 3 = 21
3k = 21 - 48
3k = - 27
k = - 27 / 3
k = - 9
Answered by
24
Answer:
k=-9 answer follow me
Step-by-step explanation:
x=3
x^3+2x^2+Kx+3=21......(1)
put value of x in eq(1)
I will get it answer
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