Math, asked by luckyllaher7257, 1 year ago

Use the remainder theorem to find the value of k,it being given that when x3+2x2+kx+3 is divided by (x-3),then remainder is 21.

Answers

Answered by Thatsomeone
70
using remainder theorem

x = 3

x^3 + 2x^2 + kx + 3 = 21

( 3 )^3 + 2 ( 3 )^2 + k ( 3 ) + 3 = 21

27 + 18 + 3k + 3 = 21

3k = 21 - 48

3k = - 27

k = - 27 / 3

k = - 9
Answered by riya171180
24

Answer:

k=-9 answer follow me

Step-by-step explanation:

x=3

x^3+2x^2+Kx+3=21......(1)

put value of x in eq(1)

I will get it answer

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