Question

use the substitution y=2x-1 to solve for x: 3(2x-1)^2+4(2x-1)-4=0. Plzz solve it fast . The answer must have two values of x and y .

Answer 1

please like the answer for the question Use the substitution = 2 − 1 to solve for x: 3(2 − 1)

2 + 4(2 − 1) − 4 = 0

Answer 2

Given:

y=2x-1

To Find:

solve for x: $3(2x-1)^{2} + 4(2x-1) - 4 = 0$

Solution:

We know that,

3(2x-1)²+4(2x-1)-4=0

By substitution, we get

3y²+4y-4=0

3y²+(6-2)y-4=0

3y²+6y-2y-4=0

3y(y+2)-2(y+2)=0

(y+2)(3y-2)=0

then,

(3y-2)=0

⇒ y=2/3

(y+2)=0

⇒ y= –2

if y = 2/3 then x = (y+1)/2 = 10/3

if y = –2 then x = (–2+1)/2 = –1/2

Hence, x = 10/3 or -1/2 and y = 2/3 or -2 respectively.