use the suitable identity to find product (3y+5) (3y+5)
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HERE'S THE ANSWER
(3y+5)(3y+5)
=> (3y+5)²
now, using identity (a+b)²= a²+b²+2ab
=>(3y)²+5²+2(3y)(5)
=> 9y²+25+30y
= 9y²+30y+25
HOPE IT HELPS
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