Use the x-intertept method to find all real solutions of the equation.
-972 - 72x2 - 96x + 36 = 3x2 + x2 – 3x + 8
Answers
Step-5 : Add up the four terms of step 4 :
(x+4) • (3x+7)
Which is the desired factorization
Equation at the end of step
5
:
(-3x - 7) • (x + 4) • (4x - 1) = 0
STEP
6
:
Theory - Roots of a product
6.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation:
6.2 Solve : -3x-7 = 0
Add 7 to both sides of the equation :
-3x = 7
Multiply both sides of the equation by (-1) : 3x = -7
Divide both sides of the equation by 3:
x = -7/3 = -2.333
Solving a Single Variable Equation:
6.3 Solve : x+4 = 0
Subtract 4 from both sides of the equation :
x = -4
Solving a Single Variable bitggchyfd 4x = 1
Divide both sides of the equation by 4:
x = 1/4 = 0.250
Plugging into the parabola formula -3.1667 for x we can calculate the y -coordinate :
y = 3.0 * -3.17 * -3.17 + 19.0 * -3.17 + 28.0
or y = -2.083
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 3x2+19x+28
Axis of Symmetry (dashed) {x}={-3.17}
Vertex at {x,y} = {-3.17,-2.08}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-4.00, 0.00}
Root 2 at {x,y} = {-2.33, 0.00}
Solve Quadratic Equation by Completing The Square
7.2 Solving 3x2+19x+28 = 0 by Completing The Square .
Divide both sides of the equation by 3 to have 1 as the coefficient of the first term :
x2+(19/3)x+(28/3) = 0
Subtract 28/3 from both side of the equation :
x2+(19/3)x = -28/3
Now the clever bit: Take the coefficient of x , which is 19/3 , divide by two, giving 19/6 , and finally square it giving 361/36
Add 361/36 to both sides of the equation :
On the right hand side we have :
-28/3 + 361/36 The common denominator of the two fractions is 36 Adding (-336/36)+(361/36) gives 25/36
So adding to both sides we finally get :
x2+(19/3)x+(361/36) = 25/36
Adding 361/36 has completed the left hand side into a perfect square :
x2+(19/3)x+(361/36) =
(x+(19/6)) • (x+(19/6)) =
(x+(19/6))2
Things which are equal to the same thing are also equal to one another. Since
x2+(19/3)x+(361/36) = 25/36 and
x2+(19/3)x+(361/36) = (x+(19/6))2
then, according to the law of transitivity,
(x+(19/6))2 = 25/36
We'll refer to this Equation as Eq. #7.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x+(19/6))2 is
(x+(19/6))2/2 =
(x+(19/6))1 =
x+(19/6)
Now, applying the Square Root Principle to Eq. #7.2.1 we get:
x+(19/6) = √ 25/36
Subtract 19/6 from both sides to obtain:
x = -19/6 + √ 25/36
Since a square root has two values, one positive and the other negative
x2 + (19/3)x + (28/3) = 0
has two solutions:
x = -19/6 + √ 25/36
or
x = -19/6 - √ 25/36
Note that √ 25/36 can be written as
√ 25 / √ 36 which is 5 / 6
Solve Quadratic Equation using the Quadratic Formula
7.3 Solving 3x2+19x+28 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 3
B = 19
C = 28
Accordingly, B2 - 4AC =
361 - 336 =
25
Applying the quadratic formula :
-19 ± √ 25
x = ——————
6
Can √ 25 be simplified ?
Yes! The prime factorization of 25 is
5•5
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 25 = √ 5•5 =
± 5 • √ 1 =
± 5
So now we are looking at:
x = ( -19 ± 5) / 6
Two real solutions:
x =(-19+√25)/6=(-19+5)/6= -2.333
or:
x =(-19-√25)/6=(-19-5)/6= -4.000
Three solutions were found :
x = 1/4 = 0.250
x = -4
x = -7/3 = -2.333
Terms and topics
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