Math, asked by datboi8, 7 months ago

Use the x-intertept method to find all real solutions of the equation.
-972 - 72x2 - 96x + 36 = 3x2 + x2 – 3x + 8​

Answers

Answered by noahparmer0
1

Step-5 : Add up the four terms of step 4 :

                   (x+4)  •  (3x+7)

            Which is the desired factorization

Equation at the end of step

5

:

 (-3x - 7) • (x + 4) • (4x - 1)  = 0

STEP

6

:

Theory - Roots of a product

6.1    A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

6.2      Solve  :    -3x-7 = 0

Add  7  to both sides of the equation :

                     -3x = 7

Multiply both sides of the equation by (-1) :  3x = -7

Divide both sides of the equation by 3:

                    x = -7/3 = -2.333

Solving a Single Variable Equation:

6.3      Solve  :    x+4 = 0

Subtract  4  from both sides of the equation :

                     x = -4

Solving a Single Variable bitggchyfd                     4x = 1

Divide both sides of the equation by 4:

                    x = 1/4 = 0.250

Plugging into the parabola formula  -3.1667  for  x  we can calculate the  y -coordinate :

 y = 3.0 * -3.17 * -3.17 + 19.0 * -3.17 + 28.0

or   y = -2.083

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = 3x2+19x+28

Axis of Symmetry (dashed)  {x}={-3.17}

Vertex at  {x,y} = {-3.17,-2.08}

x -Intercepts (Roots) :

Root 1 at  {x,y} = {-4.00, 0.00}

Root 2 at  {x,y} = {-2.33, 0.00}

Solve Quadratic Equation by Completing The Square

7.2     Solving   3x2+19x+28 = 0 by Completing The Square .

Divide both sides of the equation by  3  to have 1 as the coefficient of the first term :

  x2+(19/3)x+(28/3) = 0

Subtract  28/3  from both side of the equation :

  x2+(19/3)x = -28/3

Now the clever bit: Take the coefficient of  x , which is  19/3 , divide by two, giving  19/6 , and finally square it giving  361/36

Add  361/36  to both sides of the equation :

 On the right hand side we have :

  -28/3  +  361/36   The common denominator of the two fractions is  36   Adding  (-336/36)+(361/36)  gives  25/36

 So adding to both sides we finally get :

  x2+(19/3)x+(361/36) = 25/36

Adding  361/36  has completed the left hand side into a perfect square :

  x2+(19/3)x+(361/36)  =

  (x+(19/6)) • (x+(19/6))  =

 (x+(19/6))2

Things which are equal to the same thing are also equal to one another. Since

  x2+(19/3)x+(361/36) = 25/36 and

  x2+(19/3)x+(361/36) = (x+(19/6))2

then, according to the law of transitivity,

  (x+(19/6))2 = 25/36

We'll refer to this Equation as  Eq. #7.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (x+(19/6))2   is

  (x+(19/6))2/2 =

 (x+(19/6))1 =

  x+(19/6)

Now, applying the Square Root Principle to  Eq. #7.2.1  we get:

  x+(19/6) = √ 25/36

Subtract  19/6  from both sides to obtain:

  x = -19/6 + √ 25/36

Since a square root has two values, one positive and the other negative

  x2 + (19/3)x + (28/3) = 0

  has two solutions:

 x = -19/6 + √ 25/36

  or

 x = -19/6 - √ 25/36

Note that  √ 25/36 can be written as

 √ 25  / √ 36   which is 5 / 6

Solve Quadratic Equation using the Quadratic Formula

7.3     Solving    3x2+19x+28 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                   

           - B  ±  √ B2-4AC

 x =   ————————

                     2A

 In our case,  A   =     3

                     B   =    19

                     C   =   28

Accordingly,  B2  -  4AC   =

                    361 - 336 =

                    25

Applying the quadratic formula :

              -19 ± √ 25

  x  =    ——————

                     6

Can  √ 25 be simplified ?

Yes!   The prime factorization of  25   is

  5•5

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 25   =  √ 5•5   =

               ±  5 • √ 1   =

               ±  5

So now we are looking at:

          x  =  ( -19 ± 5) / 6

Two real solutions:

x =(-19+√25)/6=(-19+5)/6= -2.333

or:

x =(-19-√25)/6=(-19-5)/6= -4.000

Three solutions were found :

x = 1/4 = 0.250

x = -4

x = -7/3 = -2.333

Terms and topics

More Icon

Polynomial root calculator

Polynomial long division

Related links

More Icon

Root Finder -- Polynomials Calculator

How to factor five term polynomial - Yahoo Answers

Long Polynomial Division

Polynomial long division - Wikipedia

Polynomial Long Division

Polynomials - Long Division

Step-by-step explanation:

Similar questions