use thevenin's theorem to find current through 6ohm resistor. In the current shown below
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Explanation:
pd across the total RESISTANCE is 1V that is (9 - 8) .
1. 4 and 6 ohm are in parallel
R¹ = 24/10 = 2.4
2. 2.4 and 5 ohm are in series
R² = 2.4 + 5 = 7.4
I = V /R = 1/ 7.4 = 10 /74 A
3. across 6ohm, current is i then
1V = 6i + 5I = 6i + 50/74
6i = 24/74 = 12/37
i = 12 /( 6 x 37) = 2 /37A.
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