Math, asked by Anonymous, 11 months ago

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Answers

Answered by Anonymous
12
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Heyaaa mate

The answer is

Let the cup be x tea pot be y and pan be z

\boxed{Value \:of \:cup}

 x + x + x = 24

 3x = 24

=> x = \frac{24}{3}= 8

Value of cup = 8

\boxed{Value\:of\:pot}

x + y =25

 8 + y= 25

y = 25-8 = 17

Value of pot = 17

\boxed{Value\:of\:pan}

 y - z =8

 17- z= 8

 -z = 8 - 17 = -9

 z = 9

Last sum

 8 + 17 + 9 = 34

The answer is

\huge\boxed{34}

Hope it helps you

Thanks

anishranjan: congratulation bro
Answered by TheAstrophile
9
HEY DEAR MATE!!

YOUR ANSWER...

Let us consider the pot as x, the teapot as y and the vessel as z.

First equation:

x + x + x = 24

3x = 24

x =  \frac{24}{3}

x = 8

So, the value of the pot (x) is 8.

Second equation:

x + y = 25

8 + y = 25

y = 25 - 8

y = 17

So, the value of the teapot (y) is 17.

Third equation:

y - z = 8

17 - z = 8

 - z = 8 - 17

 - z =  - 9

z = 9

So, the value of the vessel (z) is 9.

Last equation:

x + y + z =  -  -

8 + 17 + 9 = 34

So, the answer is 34.

aditya9583: Hi
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