Use your data to calculate the number of water molecules to two decimal places. [4]
Moles of water H2O 11.38- 7.28 = 4.1g
Moles of anyhydrate ( CuSO4)= 7.28/159.62 = 0.0456 moles of copper sulfate
n = m/M
m = 4.1g, M = 18.02g
n = 4.1/ 18.02 = 0.227 moles of water
molecules of water 0.227(6.02 x 10^23)
= 1.37 x 10^23
Answer this:
Your value probably does not match the actual value for the hydrate. Use the following formula to calculate the percent error for the experiment. Remember to report an absolute value. [2]
Percent error = (theoretical – experimental) x 100%
theoretical
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