Question

used the factor theorem to determine whether g(x) is factor of p(x) = 9x2+6x2-5x-10, g(x) =x-1​

Answer 1

Answer:

Hi there !

No, g(x) is not a factor of p(x)

Step-by-step explanation:

to find whether g(x) is factor of p(x) put the value of X in p(x)

x-1 = 0

x = 1

p(1) = 9×2+6×2-5(1)-10

18+12-5-10

30-15

15

since, the value of p(x) is not coming as zero we conclude that g(x) is not a factor of p(x).

always remember to conclude only when the value of p(x) comes zero.

Hope it helps you !