Question

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Find the approximate value of √0.037 using differential approxmations? ​​

Answer 1

Answer;

Take y=x

Let x=0.04 and Δx=−0.003,

Then, Δy=x+Δ −x

Δy=0.037 −0.04

=Δy+0.2

Now, dy is approximately equal to $$Δy$$ and is given by

dy=(dxdy )∆x=2x1(−0.003)=

2 0.04 1 (−0.003)=−0.0075

Thus, the approximate value of

0.037

is 0.2−0.0075=0.1925

Hence, this is the answer.

hope it helps you ✌️✅✅✅

Answer 2

Answer:

Reffered to the attachment

Explanation:

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