user proper answer for the question number 12 in arithmetic progression lesson 10th CBSE maths
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here if we reverse the ap than we get 37,45............205,213.
now here a=37, d=8 and an term =213
so no of terms we can find by the formula an = a+(n-1)×d
213=37+(n-1)8
213-37=(n-1)8
176=(n-1)8
(n-1)=176÷8
n-1=22
n=22+1=23
now it's middle term=n+1÷2
23+1÷2=12
now again put following values in formula
a=37,d=8 and n=12
37+(11-1)8=37+80
=117
here is your answer 117
does this answer deserve something give a thank
now here a=37, d=8 and an term =213
so no of terms we can find by the formula an = a+(n-1)×d
213=37+(n-1)8
213-37=(n-1)8
176=(n-1)8
(n-1)=176÷8
n-1=22
n=22+1=23
now it's middle term=n+1÷2
23+1÷2=12
now again put following values in formula
a=37,d=8 and n=12
37+(11-1)8=37+80
=117
here is your answer 117
does this answer deserve something give a thank
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