Question

Usha swimming in 90 metre long pool she cover 180 metre in 1 minute boys swimming one into another and back along a straight path the average speed average velocity of Usha​

Answer 1

Answer:

Distance = 180 m

Time = 1 min = 60sec

Average speed = total distance covered / total time taken

= 180m / 60 sec

= 3m/s

Displacement = 0m/s ( as usha come back along the same path so, the intial and final position is same )

Average velocity = displacement/ time

= 0m / 60 s

= 0m/s